Answer :
Answer:
11232000
Step-by-step explanation:
Given that an identification code is to consist of 2 letters followed by 3 digits.
Also given that repetition is not permitted.
Since order matters here we find that permutation to be used.
Out of 26 letters, 2 letters can be selected without repitition in [tex]26P2[/tex] ways
And 3 codes can be selected from 10 digits in [tex]10P3[/tex] ways
Hence total number of codes = [tex]10P3(26P2)\\\\=10(9)(8) (26)(25)(24)\\=720(100)(156)\\=11232000[/tex]
No of ways = 11232000