Answer :
The temperature in degree celsius to which the gas was heated is calculated using the Charles law formula
that is V1/T1 =V2/T2
V1=88.2 ml
T1=35 +273 = 308 K
V2=123 ml
T2=?
by making T2 the formula of the subject T2=V2T1/V1
=(123 ml x308 k)/88.2 ml =429.5 K
in degree celsius = 429.5 -273= 156.5 degree celsius
that is V1/T1 =V2/T2
V1=88.2 ml
T1=35 +273 = 308 K
V2=123 ml
T2=?
by making T2 the formula of the subject T2=V2T1/V1
=(123 ml x308 k)/88.2 ml =429.5 K
in degree celsius = 429.5 -273= 156.5 degree celsius