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A 9.5-kg monkey is hanging by one arm from a branch and is swinging on a vertical circle. As an approximation, assume a radial distance of 85 cm between the branch and the point where the monkey's mass is located. As the monkey swings through the lowest point on the circle, it has a speed of 2.8 m/s. Find (a) the magnitude of the centripetal force acting on the monkey and (b) the magnitude of the tension in the monkey's arm.

Answer :

krlosdark12

Answer:

a) 88N

b) 181N

Explanation:

The centripetal force is given by:

[tex]F_c=\frac{m*v^2}{r}\\F_c=\frac{9.5kg*(2.8m/s)^2}{85*10^{-2}m}\\F_c=88N[/tex]

The tension will be equal to the centripetal force acting on the arm of the monkey plus its weight:

[tex]T=m*g+\frac{m*v^2}{r}\\\\T=9.5kg*9.8m/s^2+88N\\T=181N[/tex]

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