Answer :
[tex]\bf -3y=15-4x\implies -3y=-4x+15\implies y=\cfrac{-4x+15}{-3} \\\\\\ y=\cfrac{-4x}{-3}+\cfrac{15}{-3}\implies y=\cfrac{4}{3}x-5~\hfill \impliedby ~\hfill \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array}[/tex]