Answer :
Answer:
Final temperature, [tex]T_f=21.85^{\circ}[/tex]
Explanation:
Given that,
Mass of silver ring, m = 4 g
Initial temperature, [tex]T_i=41^{\circ}C[/tex]
Heat released, Q = -18 J (as heat is released)
Specific heat capacity of silver, [tex]c=0.235\ J/g\ C[/tex]
To find,
Final temperature
Solution,
The expression for the specific heat is given by :
[tex]Q=mc\Delta T[/tex]
[tex]Q=mc(T_f-T_i)[/tex]
[tex]T_f=\dfrac{-Q}{mc}+T_i[/tex]
[tex]T_f=\dfrac{-18}{4\times 0.235}+41[/tex]
[tex]T_f=21.85^{\circ}[/tex]
So, the final temperature of silver is 21.85 degrees Celsius.