Answer :
Answer:
Therefore, Michael concludes option C)
C)[tex](DA)^{2}=(DG)^{2}+(AG)^{2}[/tex]
Step-by-step explanation:
Given:
1. DG = 3 and the area of square DEFG is 9.
2. AG = 4 and the area of square GHIA is 16.
3. DA = 5 and the area of square ABCD is 25.
So we have,
[tex](DG)^{2}=3^{2}=9\\ \\(AG)^{2}=4^{2}=16\\\\(DA)^{2}=5^{2}=25\\[/tex]
Now Add DG² and AG² we get
[tex](DG)^{2}+(AG)^{2}=9+16=25=(DA)^{2}[/tex]
Which is also called as Pythagoras theorem i.e
[tex](\textrm{Hypotenuse})^{2} = (\textrm{Shorter leg})^{2}+(\textrm{Longer leg})^{2}[/tex]
Therefore, Michael concludes option C)
C)[tex](DA)^{2}=(DG)^{2}+(AG)^{2}[/tex]
