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The human eye is most sensitive to green light of wavelength 505 nm . Experiments have found that when people are kept in a dark room until their eyes adapt to the darkness, a single photon of green light will trigger receptor cells in the rods of the retina.1.What is the frequency of this photon?2.How much energy (in joules and eV ) does it deliver to the receptor cells?Answer in the order indicated. Separate your answers with a comma.3.To appreciate what a small amount of energy this is, calculate how fast a typical bacterium of mass 9.50�10?12 g would move if it had that much energy.

Answer :

boffeemadrid

Answer:

[tex]5.94059\times 10^{14}\ Hz[/tex]

[tex]3.93623\times 10^{-19}\ J\ or\ 2.456994766\ eV[/tex]

0.0091 m/s

Explanation:

h = Planck's constant = [tex]6.626\times 10^{-34}\ m^2kg/s[/tex]

c = Speed of light = [tex]3\times 10^8\ m/s[/tex]

[tex]\lambda[/tex] = Wavelength = 505 nm

m = Mass of bacterium = [tex]9.5\times 10^{-15}\ kg[/tex]

Frequency is given by

[tex]f=\dfrac{c}{\lambda}\\\Rightarrow f=\dfrac{3\times 10^8}{505\times 10^{-9}}\\\Rightarrow f=5.94059\times 10^{14}\ Hz[/tex]

Freqeuncy is [tex]5.94059\times 10^{14}\ Hz[/tex]

Energy is given by

[tex]E=hf\\\Rightarrow E=6.626\times 10^{-34}\times 5.94059\times 10^{14}\\\Rightarrow E=3.93623\times 10^{-19}\ J=3.93623\times 10^{-19}\times 6.242\times 10^{18}\\\Rightarrow E=2.456994766\ eV[/tex]

Energy is [tex]3.93623\times 10^{-19}\ J\ or\ 2.456994766\ eV[/tex]

The above energy is the kinetic energy

[tex]\dfrac{1}{2}mv^2=3.93623\times 10^{-19}\\\Rightarrow v=\sqrt{\dfrac{2\times 3.93623\times 10^{-19}}{9.5\times 10^{-15}}}\\\Rightarrow v=0.0091\ m/s[/tex]

The velocity of the bacterium would be 0.0091 m/s

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