Answer :
Answer:
The answer to your question is 5.019 x 10²² atoms
Explanation:
Data
mass of ammonium carbonate = 8 g
number of atoms = ?
Process
1.- Calculate the molar mass of (NH₄)₂CO₃
(NH₄)₂CO₃ = (14 x 2) + (1 x 8) + (12 x 1) + (16 x 3)
= 28 + 8 + 12 + 48
= 96 g
2.- Calculate the number of atoms
96 g ------------------ 6.023 x 10²³ atoms
8 g ----------------- x
x = (8 x 6.023 x 10²³) / 96
x = 5.019 x 10²² atoms
Answer:
There are 5.02*10^22 atoms in the beaker
Explanation:
Step 1: Data given
Mass of (NH4)2CO3 = 8.0 grams
Molar mass (NH4)2CO3 = 96.09 g/mol
Number of Avogadro = 6.022 *10^23 / moles
Step 2: Calculate moles (NH4)2CO3
Moles (NH4)2CO3 = mass (NH4)2CO3 / molar mass
Moles (NH4)2CO3 = 8.0 grams / 96.09 g/mol
Moles (NH4)2CO3 = 0.0833 moles
Step 3: Calculate atoms
Atoms = moles * number of Avogadro
Atoms = 0.0833 moles * 6.022 * 10^23 / mol
Atoms = 5.02 *10^22 atoms
There are 5.02*10^22 atoms in the beaker