Ming throws a stone off a bridge into a river below.

The stone's height (in meters above the water), xxx seconds after Ming threw it, is modeled by:

h(x)=-5(x-1)^2+45h(x)=−5(x−1)

What is the maximum height that the stone will reach?


what is the meters

Answer :

We have been given that Ming throws a stone off a bridge into a river below.

The stone's height (in meters above the water), x seconds after Ming threw it, is modeled by [tex]h(x)=-5(x-1)^2+45[/tex].

We are asked to find the maximum that the stone will reach.

We can see that our given equation is in vertex form of parabola [tex]y=a(x-h)^2+k[/tex] with vertex at point (h,k).

We can also see that leading coefficient is negative, so our given parabola is a downward opening parabola and its maximum value be at vertex.

The maximum height will be equal to y-coordinate of vertex.

We can see that vertex of our given parabola is at point (1,45). Therefore, the maximum height will be 45 meters.

Answer:

45

Step-by-step explanation:

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