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An male animal has a genotype of AaBB. The number of different gene combinations that would be found in the sex cells/sperm of this animal would be:

a) 1
b) 2
c) 4
d) 6
e) 8

Answer :

Bobanate

Answer:

B

Explanation:

Using a Punnett Square, you find that the outcomes are AB, AB, aB, and aB. There are only two unique genotypes here, so the answer is 2.

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